69 lines
2.5 KiB
Python
69 lines
2.5 KiB
Python
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# Copyright (c) 2003-2016 CORE Security Technologies
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#
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# This software is provided under under a slightly modified version
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# of the Apache Software License. See the accompanying LICENSE file
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# for more information.
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#
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# Description:
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# Generate UUID compliant with http://www.webdav.org/specs/draft-leach-uuids-guids-01.txt.
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# A different, much simpler (not necessarily better) algorithm is used.
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#
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# Author:
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# Javier Kohen (jkohen)
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#
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import re
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from random import randrange
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from struct import pack, unpack
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def generate():
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# UHm... crappy Python has an maximum integer of 2**31-1.
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top = (1L<<31)-1
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return pack("IIII", randrange(top), randrange(top), randrange(top), randrange(top))
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def bin_to_string(uuid):
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uuid1, uuid2, uuid3 = unpack('<LHH', uuid[:8])
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uuid4, uuid5, uuid6 = unpack('>HHL', uuid[8:16])
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return '%08X-%04X-%04X-%04X-%04X%08X' % (uuid1, uuid2, uuid3, uuid4, uuid5, uuid6)
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def string_to_bin(uuid):
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matches = re.match('([\dA-Fa-f]{8})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})([\dA-Fa-f]{8})', uuid)
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(uuid1, uuid2, uuid3, uuid4, uuid5, uuid6) = map(lambda x: long(x, 16), matches.groups())
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uuid = pack('<LHH', uuid1, uuid2, uuid3)
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uuid += pack('>HHL', uuid4, uuid5, uuid6)
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return uuid
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def stringver_to_bin(s):
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(maj,min) = s.split('.')
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return pack('<H',int(maj)) + pack('<H',int(min))
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def uuidtup_to_bin(tup):
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if len(tup) != 2: return
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return string_to_bin(tup[0]) + stringver_to_bin(tup[1])
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def bin_to_uuidtup(bin):
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assert len(bin) == 20
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uuidstr = bin_to_string(bin[:16])
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maj, min = unpack("<HH", bin[16:])
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return uuidstr, "%d.%d" % (maj, min)
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#input: string
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#output: tuple (uuid,version)
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#if version is not found in the input string "1.0" is returned
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#example:
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# "00000000-0000-0000-0000-000000000000 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0')
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# "10000000-2000-3000-4000-500000000000 version 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0')
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# "10000000-2000-3000-4000-500000000000 v 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0')
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# "10000000-2000-3000-4000-500000000000" returns ('00000000-0000-0000-0000-000000000000','1.0')
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def string_to_uuidtup(s):
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g = re.search("([A-Fa-f0-9]{8}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{12}).*?([0-9]{1,5}\.[0-9]{1,5})",s+" 1.0")
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if g:
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(u,v) = g.groups()
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return (u,v)
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return
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def uuidtup_to_string(tup):
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uuid, (maj, min) = tup
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return "%s v%d.%d" % (uuid, maj, min)
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